A wire has resistance R in cut into two equal pieces the two part are joined in parallel what is the resistance of combination
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Answered by
75
Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be q
Therefore R = ql/A
When it is cut then take each of the piece:-
Its resistance = q(l/2)/A = R/2
WHen joined in parallel Net resistance = R/4
Answered by
73
Let us take the length of the wire be R/2
Hope the above pic may help you
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