Question

A wire has resistance R in cut into two equal pieces the two part are joined in parallel what is the resistance of combination

Answer 1

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be q

Therefore R = ql/A

When it is cut then take each of the piece:-

Its resistance = q(l/2)/A = R/2

WHen joined in parallel Net resistance  = R/4

Answer 2

Let us take the length of the wire be R/2

Hope the above pic may help you

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