three consecutive integers are such that when they are taken in increasing orderand multiplied by 2,3 and4 respectively, they add upto 74 .find these number?
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Let the three integers be x, x+1 and x+2
If they are being multiplied
2(x)+3(x+1)+4(x+2) = 74
2x + 3x + 3 +4x + 8 = 74
9x + 11 = 74
9x = 74 – 11
9x = 63
x = 63÷9
x = 7
So the consecutive integers are 7, 8 and 9
If they are being multiplied
2(x)+3(x+1)+4(x+2) = 74
2x + 3x + 3 +4x + 8 = 74
9x + 11 = 74
9x = 74 – 11
9x = 63
x = 63÷9
x = 7
So the consecutive integers are 7, 8 and 9
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