A wire having the diameter of 1.2 mm and resistivity of 100×10^-8 Ωm at 0°C is connected across a cell of emf 1.5 V and gives a current of 10 mA. Calculate the length of wire. R=V/I
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Answer:
169.56 m
Explanation:
R = 1.5/0.01 = 150Ω
Area of cross section = 144*10^-8*3.14 =452.16*10^-8
Length of conductor = (150*452.16*10^-8)/400*10^-8
= 169.56 m
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