Question

A wire having the diameter of 1.2 mm and resistivity of 100×10^-8 Ωm at 0°C is connected across a cell of emf 1.5 V and gives a current of 10 mA. Calculate the length of wire. R=V/I​

Answer 1

Answer:

169.56 m

Explanation:

R = 1.5/0.01 = 150Ω

Area of cross section = 144*10^-8*3.14 =452.16*10^-8

Length of conductor = (150*452.16*10^-8)/400*10^-8

                                   = 169.56  m