A wire in the form of a rectangle 11m long and 8m wide is re- bent in the form of a circle . Findthe area of a circle
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perimeter of the wire ( in rectangle ) = 2(l+ b) =x where l=11m b= 8m
so
2(11+8) = x
x = 38
perimeter of the circle also = x{ leght of wire is also same )
so 2πr = 38
r = 19/π
area of the circle = 2πr^2
= 2π×19×19/π×π
2×361/π
722/π
so
2(11+8) = x
x = 38
perimeter of the circle also = x{ leght of wire is also same )
so 2πr = 38
r = 19/π
area of the circle = 2πr^2
= 2π×19×19/π×π
2×361/π
722/π
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