Question

a wire in the form of a square of side 11 cm is reshaped and bent into the form of a circle calculate the diameter of the circle so formed​

Answer 1

Answer:

14cm

Explanation:

perimeter of the square =(4*11)cm =44cm

we know that perimeter of square is equal to the perimeter of the circle.

Therefore, perimeter of the circle is also 44cm

we know the circumference of the circle =2πr

ATP, 44=2*22/7*r

let the radius be r,

therefore,

or,r=(44*7)/44 [both upper and lower 44 gets cancelled]

so we get r=7

therefore, the value of radius r is 7cm

Therefore, the value of diameter is 14cm (7*2)cm [since we know diameter=2r].

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Answer 2

Answer:

7 cm.

Explanation:

During reshaping into circle . ... Perimeter of square = perimeter of circle. => 4× 11 = 2 × 22/7 × R. => R = 7 cm.

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