A wire in the shape of a rectangle of length 18cm and width 15cm is reshaped and bent in the form of a circle. find the radius and area of the circle
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53
perimeter of rectangle=2 (length+width)
=2 (18+15)=66 cm
perimeter of circle =perimeter of rectangle
perimeter of circle=2.pi.r
66=2 x 22/7 x r
r=21/2cm
now
area of circle =pi.r^2
=22/7 x (21/2)^2=693/2
=346.5 cm^2
=2 (18+15)=66 cm
perimeter of circle =perimeter of rectangle
perimeter of circle=2.pi.r
66=2 x 22/7 x r
r=21/2cm
now
area of circle =pi.r^2
=22/7 x (21/2)^2=693/2
=346.5 cm^2
Answered by
0
Answer:
The wire is in the shape of rectangle
length = 18 cm
breadth = 15 cm
now the wire is bent into a circle
so
perimeter of rectangle = circumference of the circle
2(l+b) = 2πr
2(18 +15) = 2πr
2×33 = 2πr
66 = 2πr
66 × 7/ 2×22 = r
33 × 7/22 =r
21/2 = r
10.5 = r
so the radius of the circle is 10.5 cm
Step-by-step explanation:
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