Question

A wire in the shape of a square area 36cm sq is reshaped into a rectangle those breadth is 4 cm. what is the area of the rectangle formed

Answer 1

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here is ur answer
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area of the square =36 cm sq.
s×s=36
s=6 cm

perimeter of the square =4× s=4×6=24 cm

perimeter of the rectangle = perimeter of the square =24 cm

let the length be l

2×(l+b)=24
2l+2×4=24
2l=24-8=16
l=8 cm

so area of the rectangle =l×b=8×4=32 cm sq.

hope this helps ⚫⚫⚫⚫

Answer 2

Wire of Square is reshaped to Rectangle.
So,
Its perimeter will be equal.

But given,
$\: \: \: \: \: \: \: \: \: {s}^{2} = 36 \\ = > s = 6cm.$
So,
$\: \: \: \: \: \: \: \: 4s = 2(l+b) \\ = > 4 × 6 = 2(l+4) \\ = >(l+4) = \frac{4×6}{2} =>l= 12-4=8$

So,
Area of the wire of shape of the rectangle
$= l × b=8×4=32{cm}^{2}.$

Hope this will help you. 

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