Question

a wire in the shape of a square of side 16.5 cm is cut and bent in the shape of a circle what is the difference in the areas of these two figures

Answer 1

THE ANS IS IN THE ATTACHMENT ....

and the difference between the areas of two shapes :

346.5 - 276.25

74.25 sq.cm

Answer 2

The difference in the areas of these two figures is 251.01 sq.cm

Step-by-step explanation:

Side of square = 16.5 cm

Perimeter of square = $4 \times Side$

Perimeter of square = $4 \times 16.5 = 66 cm$

A  wire in the shape of a square of side 16.5 cm is cut and bent in the shape of a circle

So, $2 \pi r = 16.5 \\2 \times \frac{22}{7} \times r = 16.5 \\r = \frac{16.5 \times 7}{2 \times 22}$

r =2.6

Area of square =$Side^2 = 16.5^2 =272.25 cm^2$

Area of circle = $\pi r^2 = \frac{22}{7} \times 2.6^2 =21.24 cm^32$

Difference in area = 272.25 - 21.24=251.01 sq.cm.

Hence the difference in the areas of these two figures is 251.01 sq.cm.

#Learn more:

A wire in the shape of a square of side 11 metre is bent into the shape of a circle find the area of the circle​

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