a wire in the shape of a square of side 20 cm. if the wire is rebent into a rectangle of length 22 cm,find breadth. which encloses more area square or rectangle
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Perimeter of square = 4 × side
= 4 × 20
= 80cm
Now P of square = P of rectangle
80 = 2(L + B)
80 = 44 + 2B
B = 36 / 2 = 18cm
Area of aquare = side × side
= 20 × 20
= 400cm^2
Area of rectangle = L × B
= 22 × 18
= 396cm^2
Hence Area of aquare is more.
Thanks
= 4 × 20
= 80cm
Now P of square = P of rectangle
80 = 2(L + B)
80 = 44 + 2B
B = 36 / 2 = 18cm
Area of aquare = side × side
= 20 × 20
= 400cm^2
Area of rectangle = L × B
= 22 × 18
= 396cm^2
Hence Area of aquare is more.
Thanks
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