Question

A wire in the shape of a square of side 22 cm is cut out and bent again in the form of a circle. Find the area enclosed by the circular wire

Answer 1

Circumference of square will be the Circumference of circle = 4(22)=88cm

2 pi r = 104

Radius of circle = 88/(2×3.14)=14.012cm

Area = pi r^2= 3.14×(14.012)^2=616.56cm^2

Answer 2

The area enclosed by the circular wire is 616 sq. m.

Step-by-step explanation:

Since we have given that

Side of square = 22 cm

Perimeter of square = Circumference of circle

$4\times side=2\pi r\\\\4\times 22=2\times \dfrac{22}{7}\times r\\\\88=2\times \dfrac{22}{7}\times r\\\\88=r\times \dfrac{44}{7}\\\\\dfrac{88\times 7}{44}=r\\\\r=14\ m$

Area enclosed by the circular wire is given by

$\pi r^2\\\\=\dfrac{22}{7}\times 14\times 14\\\\=616\ m^2$

Hence, the area enclosed by the circular wire is 616 sq. m.

# learn more:

You are in the shape of a square of side 22 centimetre is cut and paint again in the form of a circle find the area enclosed by the circular wire

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