Question

A wire in the shape of an equilateral triangle of side 24cm is bent into the shape of a square. Find the side of the square and the area it encloses.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given :

A wire in the shape of an equilateral triangle of side 24cm is bent into the shape of a square.

To Find:

Find the side of the square and the area it encloses.

Solution:

Side of equilateral triangle = 24 cm

Perimeter of triangle = Sum of all sides = 24+24+24=72 cm

Let the side of square be x

Perimeter of square = $4 \times Side =4x$

We are given that A wire in the shape of an equilateral triangle of side 24cm is bent into the shape of a square.

So, 4x=72

x=18

Side of square = 18 cm

Area of square = $Side^2 = 18^2 =324 cm^2$

Hence The side of square is 18 cm and the area of square is 324 sq.cm.