A wire initially in the form of a circle of radius 42 vis bent into a rectangle whose sides are in the ratio 6:5 find the smaller side of the rectangle
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Answer:
Step-by-step explanation:
r=42units
circumference=2×π×r
Circumference=264units
Circumference of circle=perimeter of rectangle
Let the sides of rectangle be 6(x) and 5(x)
Then,
2【5(x)+6(x)】=264units
11(x)=132units
(x)=12
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