Math, asked by pinkesh7396, 11 months ago

A wire initially in the form of a circle of radius 42 vis bent into a rectangle whose sides are in the ratio 6:5 find the smaller side of the rectangle

Answers

Answered by asharautan8
0

Answer:


Step-by-step explanation:

r=42units

circumference=2×π×r

Circumference=264units

Circumference of circle=perimeter of rectangle

Let the sides of rectangle be 6(x) and 5(x)

Then,

2【5(x)+6(x)】=264units

11(x)=132units

(x)=12


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