A wire is 1m long, 0.2 mm in diameter and has resistance of 10 ohm. Calculate its resistivity:
Answers
Answered by
3
Here , it is Given that:
l=1m ,d=0.2mm=>r=0.1mm and R=10 ohm
by using the formula,
R= p౹/ A
= p౹/ πr²
therefore, p= Rπr²/l
= 10× 3.14×( 0.1× 10 -³)²
= 10× 3.14× 0.1×0.1× 10 to the power -6
= 0.314× 10 to the power-6
= 3.14× 10 to the power-7 ohm- m
hence, the resistivity of the conductor is 3.14× 10 to the power-7 ohm- m
bharat08:
please mark it as brainliest
Answered by
3
Answer:
Explanation:
Here , it is Given that:
l=1m ,d=0.2mm=>r=0.1mm and R=10 ohm
By using the formula,
R= p౹/ A
= p౹/ πr²
Therefore, p= Rπr²/l
= 10× 3.14×( 0.1× 10 -³)²
= 10× 3.14× 0.1×0.1× 10 to the power -6
= 0.314× 10 to the power-6
= 3.14× 10 to the power-7 ohm- m
Hence, the resistivity of the conductor is 3.14× 10 to the power-7 ohm- m
Similar questions