Question

A wire is (7x-3) m long. A length of (3x-4)m is cut for use.
1) How much wire is left?
2) If this left out wire is used for making an equilateral triangle. What is the length of each side of the triangle so formed?

Answer 1

Answer:

Step-by-step explanation:Given length of the wire = ( 7x - 3 ) m

Length of Wire used = ( 3x - 4 ) m

= Original length of wire - Length of wire used

= ( 7x - 3 ) - ( 3x - 4 )

= 7x - 3 - 3x + 4

= 4x - 7

Hence,

Now, Length of wire which is left is used to make an equilateral triangle.

So, the wire length will be equal to  of the triangle.

As we know that the length of side of equilateral triangle is same.

Let, each side of equilateral triangle = 'a' cm

•°•

4x - 7 = 3 ( a )

a = ( 4x - 7 ) / 3

Hence,

Hence, <b><u>Side of equilateral triangle is ( 4x - 7 ) / 3 m.</b></u>

Answer 2

Answer:

1) (4x-7)m

Step-by-step explanation:

Length of wire = (7x-3)m

Cutted wire = (3x-4)m

Such that wire is left = (7x-3)

-(3x-4) m

Ans: ( 4x-7)m