Question

A wire is (7x-3) meter is long. A length of (3x-4) is cut for use .how much wire is left and the left wire is bend as a square then what is the length of each side.

Answer 1

Answer :-

• The length of the wire left is (4x + 1)metres.

• The left wire is bend as a square then, what is the length of each side is x + ¼ metres.

Step-by-step explanation:

To Find :-

• How much wire is left.
• The left wire is bend as a square then, what is the length of each side.

Solution:

Given that,

• Length of the wire = ( 7x - 3 ) metres
• Length of the wire cut for use = ( 3x - 4 ) metres

Therefore,

• Length of the wire left :-

=> ( 7x - 3 ) metres - ( 3x - 4 ) metres

=> 4x + 1 metres

Hence,

The length of the wire left is (4x + 1 )metres.

Now,

• The left wire is bend as a square then, what is the length of each side.

We got,

• Length of left wire = ( 4x + 1 ) metres,

Therefore, ( 4x + 1 ) metres is the perimeter of square, as the left length wire is bent to square

As we know that,

Perimeter of square = 4 × side,

=> 4 × side = 4x + 1

=> side = ( 4x + 1 ) ÷ 4

=> side = x + ¼

Hence,

The left wire is bend as a square then, what is the length of each side is (x + ¼) metres.