A wire is (7x – 3) metres long. A length of (3x – 4) metres is cut for use (a) How much wire is left? (b) If this left out wire is used for making an square. What is the length of each side of the square so formed?
Answers
Step-by-step explanation:
Given length of the wire = ( 7x - 3 ) m
Length of Wire used = ( 3x - 4 ) m
< b > Wire left – < /b ><b>Wireleft–</b>
= Original length of wire - Length of wire used
= ( 7x - 3 ) - ( 3x - 4 )
= 7x - 3 - 3x + 4
= 4x - 7
Hence, < b > < u > ( 4x - 7 ) m of wire is left. < /b > < /u ><b><u>(4x−7)mofwireisleft.</b></u>
Now, Length of wire which is left is used to make an equilateral triangle.
So, the wire length will be equal to < b > perimeter < /b ><b>perimeter</b> of the triangle.
As we know that the length of side of equilateral triangle is same.
Let, each side of equilateral triangle = 'a' cm
< u > Perimeter of equilateral triangle = 3 ( a ) < /u ><u>Perimeterofequilateraltriangle=3(a)</u>
•°•
4x - 7 = 3 ( a )
a = ( 4x - 7 ) / 3
Hence, < b > < u > Side of equilateral triangle is ( 4x - 7 ) / 3 m. < /b > < /u ><b><u>Sideofequilateraltriangleis(4x−7)/3m.</b></u>
Answer:
Original length of the wire = (7x – 3) metres
After cutting a length of (3x – 4) m for use,
(a) therefore, length of wire left
= (7x – 3) – (3x – 4)
= 7x – 3 – 3x + 4
= (4x + 1) metres
(b) if the left out wire is used to make a square,
length of each side of the square so formed
= (4x + 1) / 4
= (x + 1/4) metres