Question

A wire is 7x−3meters long. A length of 3x−4meters is cut for use.a)How much wire is left?b)If this left out wire is used for making an equilateral triangle, what is the length of each side of the triangle so formed?

Answer 1

Answer:  Length of wire = 7x-3 m

               Wire cut for use = 3x-4 m

                So, wire left = 7x-3 - (3x-4) m

                                      = 7x-3-3x+4 m

                                      = 4x+1 m

         now length of each side of the triangle = 4x+1/3 m

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Answer 2

Step-by-step explanation:

a) wire that is left

= 7x-3-3x+4

=4x+1 meters

b) length of each side of the eq. triangle

=(4x+1)/3 meters