Question

A wire is along the boundary of a circle with radius 28 cm. If the same wire is bent in the form of a square, find the aresa of the square formed.

Answer 1

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Length of the wire = Circumference of the circle

$= 2 \pi r$

$=2 * 22/7 * 28$

$= 2* 22 * 4$

$= 176 cm$

Now this wire is bent in the shape of a square,

So each side will be,

$= 176/4$

$= 44 cm$

Now,

Area,

$= s^2$

$= 44^2$

$= 1936 cm^2$

Answer 2

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If a wire is bent along the boundary  of a circle then to a square.In that case the circumference  of circle and the square will be equal.

So,
     Circumference of circle = Perimeter of square

     2 x π x radius of circle = 4 x  side 

    2 x π x 28 cm = 4 x side

    2 x ( 22/7 ) x 28 cm = 4 x side

    2 x 22 x 4 cm = 4 x side

    side = 2 x 22 x 4 cm / 4

   side = 44 cm.


Area of a square = side²

                            = ( 44 cm )²

                            = 1,936 cm².

So, the area enclosed by that wire is 1,936 cm².

         
                                               ☺☺☺