A wire is bent in the form of a squre of side 16.5cm .it is straightened and then bent into a circle what is the radius of the circle so formed ?
Answers
Answered by
8
Perimeter of square=4×16.5
=66cm
Perimeter of square=Perimeter of circle
66=2πr
33=πr
33×7/22=r
10.5cm =r
=66cm
Perimeter of square=Perimeter of circle
66=2πr
33=πr
33×7/22=r
10.5cm =r
Answered by
2
here side of square is s=16.5
perimeter of square is 4s
=>4*16.5
=>perimeter is 66 cms which is length of wire and this length of wire becomes circumference of circle .
hence circumference of circle is 2πr=66
=>2*3.14*r=66
=>r=10.5 cm is the radius of circle
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