a wire is bent in the form of square of 27cm side, the wire is straightened and bent into form of semi circle, find radius of semi circle so formed?
Answers
✯Given✯
➪ Side of square formed = 27 cm
✯To find✯
➪ Radius of semi circle formed = ?
✯Analyzation of the question✯
➪ A wire is bent in the form of square
➪ Then the wire is straightened and formed into semi circle
➪ We shall find the radius of that semi circle formed
✯Solution✯
➪ Length of the wire = Perimeter of the square = 27 × 4 = 108 cm
➪ When the wire is bent into the form of semi circle, then we can clearly say that the perimeter of the semi circle will be 108 cm
➪ Now, let r be the radius of the semi circle
➪ Then it's perimeter = r ( π + 2 )
➪ Then it's perimeter = r ( ²²⁄₇ + 2 )
➪ Then it's perimeter = 36r ÷ 7 cm
➪ We know the perimeter, equate it
➪ 36r ÷ 7 = 108
➪ r = 108 × 7 ÷ 36
➪ r = 21 cm
∴ The radius of the semi circle so formed is 21cm
Step-by-step explanation:
A wire is bent into the form of a square of side
27 cm. The wire is straightened and bent into the
form of a semi-circle. What will be the radius of
the semi-circle so formed?