A wire is bent in the shape of a rectangle. Its length is 36
cm and breadth is 25 cm. If the same wire is bent in the
shape of a square, what will be the measure of its side?
Among these two shape which shape occupies more area?
Answers
Answered by
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Heya !!!
Here is your answer
Length of rectangle = 36cm
Breadth of rectangle = 25cm
Perimeter of rectangle = 2(25+36)
Perimeter = 122 cm
Area of rectangle = l*b
Area. = 36*25
Area = 900cm square.
The same wire is bent to form square , therefore
Perimeter of square = 4s
Perimeter of square and perimeter of rectangle will be same
Therefore, perimeter of square = perimeter of rectangle
4s = 122cm
s = 122/4
s = 30.5 cm
Area of square = s*s
Area = 930.25 cm square
Therefore, area of square is more than that of rectangle.
Hope it helps
Pls mark my answer as brainliest :-)
Greetings
Kushagra
Here is your answer
Length of rectangle = 36cm
Breadth of rectangle = 25cm
Perimeter of rectangle = 2(25+36)
Perimeter = 122 cm
Area of rectangle = l*b
Area. = 36*25
Area = 900cm square.
The same wire is bent to form square , therefore
Perimeter of square = 4s
Perimeter of square and perimeter of rectangle will be same
Therefore, perimeter of square = perimeter of rectangle
4s = 122cm
s = 122/4
s = 30.5 cm
Area of square = s*s
Area = 930.25 cm square
Therefore, area of square is more than that of rectangle.
Hope it helps
Pls mark my answer as brainliest :-)
Greetings
Kushagra
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