Question

a wire is bent in the shape of a square of side 66 cm. if the same wire is loop in the form a circle, what will be the radius of the circle?​

Answer 1

Answer:

Length of wire = 4a

= 4 × 66 cm

= 264 cm

Now,

circumference of circle = Length of wire

2 π r = 264 cm

r = (264 cm) / (2 π)

= 42 cm.........(take π = 22/7)

Radius of circle is 42 cm.

Answer 2

Given :–

• Side of a square = 66cm.
• The same wire is loop in the form of a circle.

To Find :–

• Radius of a circle.

Solution :–

First, we have to find the length of wire.

So,

Length of a wire = 4a

• Side = a = 66cm.

→ 4 × 66cm

→ 264cm

Now,

We have to find the radius of a circle.

According to the question,

• Circumference of circle = Length of a wire.

It means,

• 2πr = 264cm

Let,

→ $\pi = \dfrac{22}{7}$

→ 2 × $\dfrac{22}{7}$ × r = 264cm

→ r = $\dfrac{\cancel{264} \times 7}{2 \times \cancel{22}}$

→ r = $\dfrac{\cancel{132} \times 7}{\cancel{2} \times 11}$

→ r = $\dfrac{\cancel{66} \times 7}{1 \times \cancel{11}}$

→ r = $\dfrac{6 \times 7}{1 \times 1}$

→ r = $\dfrac{42}{1}$

→ r = 42cm.

Hence,

The radius of a circle is 42cm.