Math, asked by jafarzehen, 7 months ago

A wire is bent in the shape of an equilateral triangle of each side 44cm. It is rebent to form a circular ring. What is the diameter of the ring?

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Answers

Answered by jafar7
1

Answer:

Don't know bro sorry

It very hard

Answered by chetnabhati
7

Step-by-step explanation:

it's each side of equilateral triangle is equals to 44 CM so,

the perimeter of equilateral triangle is equals to 132 CM

if this wire is bent into a circle the perimeter of circumference of the circle is equals to 132 CM

then

circumference of circle =2πr 132=2(22/7)r

132(7)/(22)(2)=r

(66)(7)/22=r

r=3(7)

r=21cm

diameter=21(2)

=42 cm

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