A wire is bent in the shape of an equilateral triangle of each side 44cm. It is rebent to form a circular ring. What is the diameter of the ring?
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Answers
Answered by
1
Answer:
Don't know bro sorry
It very hard
Answered by
7
Step-by-step explanation:
it's each side of equilateral triangle is equals to 44 CM so,
the perimeter of equilateral triangle is equals to 132 CM
if this wire is bent into a circle the perimeter of circumference of the circle is equals to 132 CM
then
circumference of circle =2πr 132=2(22/7)r
132(7)/(22)(2)=r
(66)(7)/22=r
r=3(7)
r=21cm
diameter=21(2)
=42 cm
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