Physics, asked by tamanna1234aggarwal, 4 months ago

Q5/54 1 mole of Argon gas (molar mass = 40 g/mol) at 460 K is mixed in a
rigid, insulated container with 1 mole of Nitrogen gas (molar mass = 28 g/mol)
at 300 K. After equilibrium is attained:
(R is the gas constant)

a. The total kinetic energy of the molecules of the gas mixture is 1440R

b. The temperature of the gas mixture is 360 K

c. The ratio of the root mean square speed of Argon molecules to the root mean square speed of Nitrogen molecules is √10/√7

d. The ratio of the total kinetic energy of Argon molecules to the total kinetic energy of
Nitrogen molecules is
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Answers

Answered by RUPAMCHAKRABORTY
0

Answer:

Q5/54 1 mole of Argon gas (molar mass = 40 g/mol) at 460 K is mixed in a

rigid, insulated container with 1 mole of Nitrogen gas (molar mass = 28 g/mol)

at 300 K. After equilibrium is attained:

(R is the gas constant)

a. The total kinetic energy of the molecules of the gas mixture is 1440R

b. The temperature of the gas mixture is 360 K

c. The ratio of the root mean square speed of Argon molecules to the root mean square speed of Nitrogen molecules is √10/√7

d. The ratio of the total kinetic energy of Argon molecules to the total kinetic energy of

Nitrogen molecules is

Answered by samrita84
1

Answer:

a.

The relation between the gas pressure P and average kinetic energy per unit volume E is. [ CBSE PMT ... (a) 1440 kPa ... The ratio of molecules in the two containers will then be. (a ). 1. 1.

b. ☝️☝️☝️☝️ pic

c.

Molecular mass of nitrogen, M = 28.0 g = 28 × 10. –3 kg. The root mean square speed of nitrogen is given by the relation: vrms = √. 3RT m.

d.

Kinetic theory gives insight into the behavior of gases on a microscopic scale. In this section, we derive an equation that ...

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