A wire is bent into a circular shape of radius 28 cm. it is bent in the form of a square, what will be its area?
sangeetha57:
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54
Heyy mate ❤✌✌❤
Here's your Answer....
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Circumference of a circle = 2 ×pie × r
= 2 × 22/7 × 28
= 2 × 22 × 4
= 44 × 4
= 176cm.
Perimeter of Square = Circumference of circle
4 × side = 176
side = 176 / 4
side = 44cm.
Area of Square = Side × side
= 44 × 44
= 1936 cm^2.
✔✔
Here's your Answer....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Circumference of a circle = 2 ×pie × r
= 2 × 22/7 × 28
= 2 × 22 × 4
= 44 × 4
= 176cm.
Perimeter of Square = Circumference of circle
4 × side = 176
side = 176 / 4
side = 44cm.
Area of Square = Side × side
= 44 × 44
= 1936 cm^2.
✔✔
Answered by
43
ATQ, A wire is bent into a circular shape of radius 28 cm then the same wire is bent in the form of a square.
=> circumference of the circle = perimeter of the square
here, we have to find the area of the square. so first we have to find it's side.
given radius of the circle = 28cm
circumference = 2πr
= 2 × 22/7 × 28
= 44 × 4
= 176cm
therefore perimeter of the square = 176cm
=> 4 × side = 176cm
=> side = 176/4
=> side = 44cm
hence, the side of the square is 44cm.
now let's find it's area..
area of the square = side²
= 44 × 44
= 1936cm²
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