Math, asked by sangeetha57, 1 year ago

A wire is bent into a circular shape of radius 28 cm. it is bent in the form of a square, what will be its area?


sangeetha57: please answer the question
gegfhfhbduwobshakdbs: which question?

Answers

Answered by AJThe123456
54
Heyy mate ❤✌✌❤

Here's your Answer....

⤵️⤵️⤵️⤵️⤵️⤵️⤵️⤵️

Circumference of a circle = 2 ×pie × r

= 2 × 22/7 × 28

= 2 × 22 × 4

= 44 × 4

= 176cm.

Perimeter of Square = Circumference of circle

4 × side = 176

side = 176 / 4

side = 44cm.

Area of Square = Side × side

= 44 × 44

= 1936 cm^2.
✔✔

AJThe123456: please mark it as brainliest
sangeetha57: thank you
AJThe123456: please mark it as brainliest
AJThe123456: Can you please mark its as brainliest
Answered by gegfhfhbduwobshakdbs
43

 \large \tt AHOY!! \:

ATQ, A wire is bent into a circular shape of radius 28 cm then the same wire is bent in the form of a square.

=> circumference of the circle = perimeter of the square

here, we have to find the area of the square. so first we have to find it's side.

given radius of the circle = 28cm

circumference = 2πr

= 2 × 22/7 × 28

= 44 × 4

= 176cm

therefore perimeter of the square = 176cm

=> 4 × side = 176cm

=> side = 176/4

=> side = 44cm

hence, the side of the square is 44cm.

now let's find it's area..

area of the square = side²

= 44 × 44

= 1936cm²

 \large \tt HOPE \:  THIS \:  HELPS!!


Similar questions