Question

A wire is bent into square. The area of square is 121 m2

. If the same wire is bent to form a

circle. Find its area.​

Answer 1

${ \huge{ \color{pink}{ \underline{ \underline{ \sf{ \color{aqua}{คຖŞຟēr}}}}}}}$

Given, Area of square= 121m²

Area=(side)²

$\sf{side = \sqrt{121} = 11}$

side=11 m

Perimeter of square= 4×side

=11×4=44m

Circumference of circle= 44m

$\sf{2\pi r = 44}$

$= > 2 \times \frac{22}{7} \times r = 44$

$= > r = \frac{44 \times 7}{22 \times 2}$

$= > r = \frac{ \cancel{44 } \times 7}{ \cancel{22} \times \cancel{2}} = 7$

So radius of circle=7m

$\sf{Area \: of \: circle=\pi {r}^{2} }$

$= > \frac{22}{7} \times 7 \times 7 = 154 {m}^{2}$

${\large { \color{aqua} {\boxed{ \color{pink}{\sf {❥Hope \: it \: helps \: you....}}}}}}$

Answer 2

Done by Aritra kar.

Hope you are looking for this answer closely.

$perimeter \: of \: circle \: =2 \pi \: r \: \\area \: of \: circle = \pi \: {r}^{2}$