A wire is bent to form a square of a side 20cm . if the same wire is bent to form a rectangle of length 14cm . find it's breadth and area of the rectangle
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the perimeter of square is 4×20
=80
the peramater of square =perimeter of rectangle
80=2(l+b)
80/2=(40+b
40=40+b
b=0
area=l×b
14×0=0
=80
the peramater of square =perimeter of rectangle
80=2(l+b)
80/2=(40+b
40=40+b
b=0
area=l×b
14×0=0
Answered by
0
the perimeter of square is 4×20=80
the peramater of square =perimeter of rectangle
80=2(l+b)
80/2=(40+b)
40=40+b
40/40=b
b=0
area=l×b
14×0=0
the peramater of square =perimeter of rectangle
80=2(l+b)
80/2=(40+b)
40=40+b
40/40=b
b=0
area=l×b
14×0=0
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