Question

A wire is carrying a current to 2.5 amp how much charge will pass through it in 20 min ?Also find the no. of electrons passing through it per second

Answer 1

current (I) = q(charge) /(time in second)

2.5 = q / ( 20 x 60)
q = 3000 Culamb

and q = ne , here e = charge of electron

=no. of electron
= n = q/e = 3000 / (1.6 x 10^-19) = 1875 x 10^19 = 1.875 x 10^22 


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