Solve thiz sum if u hve dare to it..
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in opl
(pr/2)^2+a^2=r^2......(1)
in triangle omp
b^2+pm^2=r^2......(2)
pq=2pm=2pr
pm=pr
therefore (2) becomes
b^2+(pr) ^2=r^2
substitute value of (pr) from (1) in (2)....
u will get ans
(pr/2)^2+a^2=r^2......(1)
in triangle omp
b^2+pm^2=r^2......(2)
pq=2pm=2pr
pm=pr
therefore (2) becomes
b^2+(pr) ^2=r^2
substitute value of (pr) from (1) in (2)....
u will get ans
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