Math, asked by subisebastian3377, 1 year ago

A wire is cut into several pieces . Each of the small piece is bent into a square of side 2cm. If the total area of the small squares is 28 square cm, what was the original length of the wire?

Answers

Answered by Anonymous
34

Answer:

56 cm

Step-by-step explanation:

Each square has side 2 cm, so has area 4 cm².

The total area of the squares is 28 cm², so there are 28 / 4 = 7 squares.

Each square uses 4 × 2 cm = 8 cm of wire for its perimeter.

So the length of wire is 7 × 8 cm = 56 cm.

Answered by Anonymous
15

area of each small square=2×2=4cm square

given that total area of all square=28

hence,no. of square=28/4=7

perimeter of each square=4×2=8cm

total length of wire=8×7=56

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