A wire is drawn such that it radius change from r and 2r the new resistance is _____
Answers
Answer ⤵️⤵️
The resistance can be determined by the formula R = rho* L/A where rho is the resistivity of the material, L is the length and A is the cross-sectional area of the wire.
The resistance of the wire is given as R.
So this can be written as:
R = rho* L/(π r^2).
After the radius of its cross-section is doubled, we get the new resistance as:
R' = rho* L / ( π(2r)^2) = rho* L/( π (4*r^2))
So, on comparing the initial and final resistance, we find that the new resistance is 1/4th of the original resistance.
New radius =2r
New area =4 pi r^2
Area is inversely proportional to resistance
New resistance would be 1/4of the original resistance
Hope it helps uh ❤️༄
Explanation:
Answer ⤵️⤵️
The resistance can be determined by the formula R = rho* L/A where rho is the resistivity of the material, L is the length and A is the cross-sectional area of the wire.
The resistance of the wire is given as R.
So this can be written as:
R = rho* L/(π r^2).
After the radius of its cross-section is doubled, we get the new resistance as:
R' = rho* L / ( π(2r)^2) = rho* L/( π (4*r^2))
So, on comparing the initial and final resistance, we find that the new resistance is 1/4th of the original resistance.
New radius =2r
New area =4 pi r^2
Area is inversely proportional to resistance
New resistance would be 1/4of the original resistance
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Hope it helps uh ❤️༄