Question

a wire is in a shape of rectangle its length is 40 cm and breadth is 22 CM if the same wire is ribbon in the shape of a square what will the measure of each side and also find which shape and closes more area

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!}}}$

Length of rectangle= 40 cm
Breadth of rectangle= 22 cm

ATQ,
Perimeter of rectangle= Perimeter of square

So, perimeter of rectangle=2(l+b)
=2×(40+22)
=2×66
=132 cm

Perimeter of square,
$4 \times side = 132 \\ side = \frac{132}{4} \\ side = 33cm$
Therefore, Side of square is 33 cm.

Area of rectangle=l×b
=40×22
$= 880 {cm}^{2}$

Area of square
$(side) {}^{2} \\ = (33) {}^{2} \\ = 1089 {cm}^{2}$

Therefore, Square covers more area than rectangle.

Hope it helps you.

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Answer 2

Hey Mate!!

Given
Length of rectangle=40cm
Breadth of rectangle=22cm

As per the question,
Perimeter of rectangle=Perimeter of square

So, Perimeter of rectangle=2(l+b)
=2(22+40)
=2×62
=124cm

Now, Perimeter of square
$= 4 \times side$
So, One side
$= \frac{132}{4} \\ = 33cm$
Area of rectangle =l×b
=22×40
=880cm^2

Area of square = (side)^2
=33×33
=1089cm^2

So square covers more area than rectangle.

Hope it helps.