a wire is in the form of a circle of radius 21 cm it is bent into an equilateral triangle find the area of the triangle
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circumference of circle=2πr=2×22/7×21=2×22×3=44×3=132 cm
perimeter of eq. ∆=circumference of circle
3a=132
a=132/3=44cm
area of eq. ∆=√3/4a^2=√3/4 =√3/4×44×44=√3×11×44=484√3 cm^2
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