Question

a wire is in the form of a square of side 16 cm it is bent to make a triangle of side 10 cm find the length of the triangle formed find which one is more area
$2(l + b)$
​

Answer 1

Let a be the side of a square, l be the length and b be the breadth of rectangle.

As length of wire is constant, perimeter of both shapes would be same,

⇒4a=2(l+b)

⇒40=2(12+b)

⇒b=18 cm

Area of square=a

2

=10

2

=100cm

2

Area of rectangle=lb=12×18=216cm

2

⇒ Area of rectangle is greater by 116cm

2

.