Question

a wire is in the shape of a rectangle .its length is 40 cm and breadth is 22 cm .if the same wire is given the shape of a square what will be the measure of each side ? also find which shape-rectangle or square -encloses more area?​

Answer 1

Answer:

Step-by-step explanation:

given  

l=40 cm ,b =22cm

to find length of wire ,

circumstance of rectangle =2(l+b)

                                          =2(40+22)

                                          =132cms

so ,one side of spuare  a =132/4

                                          =33cm

area of rectangle =l ×b

                           =40×22

                          =×880cm²

area of square =a³  = 33²  =1089 cm²

hence square enclosed more area.

Answer 2

⭐ Question

A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side. Also find which shape encloses more area?

${\underline{\bf { Given \: that } }}$

• A wire is in the shape of a rectangle has length of 40 cm and breadth of 22 cm.

${\underline{\bf { To \: find: } }}$

• If the same wire is rebent in the shape of a square, what will be the measure of each side.

• Also find which shape encloses more area and by how much?

${\underline {\bf { Solution : } }}$

According to question-

$\rm\blue {Perimeter \: of \: rectangle = Perimeter \: of \: square </p><p>}$

$\rm { \therefore 2(Length + Breadth) = 4 \times Side </p><p>}$

$\rm { \longrightarrow 2 (40 + 22) = 4 \times Side </p><p>}$

$\rm { \longrightarrow 2 \times 62 = 4 \times Side </p><p>}$

$\rm { \longrightarrow 124 = 4 \times Side </p><p>}$

$\rm { \longrightarrow Side = \dfrac{124}{4}</p><p>}$

$\rm\red { Side = 31 cm}$

Now,

$\rm {\implies Ar. \: of \:rectangle = length \times breadth }$

$\rm {\implies Ar. \: of \:rectangle = 40 \times 22 = 880 {cm}^{2} }$

and,

$\rm { \implies Area \: of \: square = {(Side)}^{2} }$

$\rm { \implies 31 \times 31 = 961 {cm}^{2} </p><p>}$

$\rm\purple { 880 {cm}^{2} < 961 {cm}^{2} }$

Therefore, the square-shaped wire encloses more area.