Question

A wire is in the shape of a rectangle. Its length is 40cm and breadth is 22 cm. The same wire is rebent in the shape of a square. Which shape encloses more area?

Answer 1

Answer

Square

Solution:

Length= 40cm

Breadth= 22cm

Perimeter of the rectangle= Length of the wire

=2(l+b)= 2(40cm + 22cm)

=2\times622×62cm = 124cm

Now, the wire is rebent into a square.

Perimeter= 124cm

4\times side=1244×side=124

Therefore side= \frac{124}{4}4124cm= 31cm

So, the measure of each side= 31cm

Area of rectangular shape= l\times bl×b

=40cm\times22cm40cm×22cm

=880cm^2880cm2

Area of a square shape= \left(Side\right)^2(Side)2

=\left(31\right)^2=961cm^2(31)2=961cm2

Since 961cm^2\ >\ 880cm^2961cm2 > 880cm2

Hence, the square encloses more area.

Answer 2

thank you so much for these answers