Question

A wire is in the shape of a rectangle of length 12 cmand breadth 8 cm. The same wire is rebent into a square. Find it's area.​

Answer 1

Answer:

100 cm²

Step-by-step explanation:

The perimeter of the rectangle will be the same as the perimeter of the square as it is the same wire which is rebent

Perimeter of rectangle = 2(l + b)

= 2(12 + 8)

= 40 cm

Perimeter of square = 4s

4s = 40

s = 10 cm

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Now,

Area of square = side²

= 10²

=100 cm²

Therefore the area of the square is 100 cm²

Answer 2

Answer:

$100cm {}^{2}$

Step-by-step explanation:

Given A wire is in shape of rectangle

where

length= 12cm.

breadth=8cm.

Perimeter of rectangle =2(l+b)

=2(20)

[Perimeter = 40 cm.]

now of wire is bent in shape of square

where side = a cm

now

Perimeter of rectangle = perimeter of square

40=4a

[a=10cm]

side of square formed is 10 cm..

therefore area of square will be 10×10 = 100cm^2

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