Question

A wire is in the shape of a rectangle of length 40 cm and breadth 22 cm. if the same wire is again benrt in the shapenof a square,what will we be the measure of each side? also find which shape enclosebmore area?​

Answer 1

Answer:

length of rectangle= 40 cm

breadth of rectangle= 22 cm

so, perimeter= (40+22)*2

= 62*2

=124 cm

so, sides of square= 124/4= 31cm

so the measure of sides of square is 31 cm and both the shape will enclose same area

I want to reach next rank so please mark me as brainliest

Answer 2

Given :-

• A wire is in the shape of a rectangle of length 40 cm and breadth 22 cm.

To Find :-

• If the same wire is again bent in the shape of a square, what will we be the measure of each side ?

• Which shape enclose more area ?​

Solution :-

As we know that,

Here, Perimeter = Length of wire

[ And it will remain same when you will change the shape of wire ]

★ Perimeter of Rectangle = 2( length + breadth )

★ Perimeter of Square = 4 × Side

★ Area of Rectangle = Length × Breadth

★ Area of Square = Side × Side

• ~When wire is bent in shape of rectangle :

Finding the perimeter :-

⟶ 2( 40 cm + 22 cm )

⟶ 2( 62 cm )

⟶ 2 × 62 cm

⟶ 124 cm

Finding the area :-

⟶ 40 cm × 22 cm

⟶ 880 cm²

• ~When wire is bent in shape of square :

[ Perimeter of rectangle = Perimeter of square , because length of wire remains same ]

Finding side :-

⟶ 4 × side = 124 cm

⟶ Side = 124 cm ÷ 4

⟶ Side = 31 cm

Finding the area :-

⟶ 31 cm × 31 cm

⟶  961 cm²

We can see that,

• Area of square ( 961 cm² ) > Area of rectangle ( 880 cm² )

Hence,

• Measure of each side when wire is bent into square shape is 31 cm

• Square shaped wire enclose more area.