Question

A wire is in the shape of a rectangle whose dimensions are 46cm×30cm.if. if the same wire is rebent in the shape of a square .find the side of square?

Answer 1

L. 46cm

B. 30cm

p of rec. 2(l+b)

2(46cm+30cm)

152

p of sq. side×side. 152

2x. 152

x. 152÷2

x. 76

Answer 2

$\underline{\huge\mathfrak{Answer}}$

Given , the dimensions of the rectangularly plotted wire =

$46 \times 30$cm .

Therefore ,

perimeter of the wire =

$2(l + b)$

$= 2(46 + 30)$

$= 2 \times 76$

$= 152 \: {cm}^{3}$

Since , the same wire is rebent in the shape of a square , Therefore ,

$Perimeter \: of \: the \: square \: = \: Perimeter \: of \: the \: rectangle$

$= > 4 \times l = 152$

$= > l = \frac{152}{4}$

$= > l = 38 Therefore , the sides of the square would be = [tex]38 cm$