A wire is in the shape of a square of side 10 cm .If the wire is rebent into a rectangle of length 12 cm, find its breadth .which figure encloses more area and by how much ?
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first we have too find the area of the square by keeping 10cm as the side . then we have to find the perimeter of the square . however the length of the wire is the same in two geometric shapes that is the perimeter is same . by that we can find out the breadth by the formula l*b.
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Side of a square = 10cm
⠀⠀⠀Perimeter of square = 4 × S
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 4 × 10 = 40cm².
Perimeter of sq. = Perimeter of rectangle =40cm²
Perimeter of rectangle = 2 ( L + B )
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 2 ( 12 + B )
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 = 24 + 2B
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀40 - 24 = 2B
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B =
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀B = 8cm.
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Area of sq. = S × S
⠀⠀⠀⠀⠀⠀⠀= ( 10 × 10 ) cm²
⠀⠀⠀⠀⠀⠀⠀= 100 cm²
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Area of rectangle = ( L × B ) sq. unit
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = ( 12 × 8 ) cm²
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 96 cm².
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Square has encloned more area by 4cm² .
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