A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of length 12 cm, find its breadth. *
1 point
8 cm
None of these
10 cm
25/3 cm
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Perimeter of the square = 4× side
=> 4×10
= 40 cm
As the wire is bent into rectangle having length 12 cm
Since Perimeter of square = Perimeter of rectangle
40= 2(l+b)
20= 12+b
b= 8 cm
Area of square = 10²= 100 cm²
Area of rectangle= l×b= 12×8= 96cm²
Lost in area = 100-96= 4cm²
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