Question

A wire is in the shape of rectangle. It's length is 40 cm and breadth is 22cm if same wire is rebent in the shape of a square what will be measure of each side. Also find shape of enclosed area. ​

Answer 1

Answer:Solution:

Length of wire = 40 cm

Breadth of wire = 22 cm

=> Perimeter of Wire = 2 ( l + b )

=> Perimeter = 2 ( 40 + 22 )

=> Perimeter = 2 ( 62 ) = 124 cm

Hence perimeter of wire in the shape of rectangle is 124 cm.

Now it is in the form of square. So let us assume the side to be 'a'.

=> Perimeter of Square = Perimeter of Rectangle

=> 4 a = 124

=> a = 124 / 4 = 31

Hence one side of a square is 31 cm.

Area of Rectangle = l × b

=> Area of Rectangle = 40 × 22 = 880 cm²

Area of Square = a²

=> Area of Square = 31 × 31 = 961 cm²

So the area covered by square is more than that of area covered by rectangle.

Area Difference = 961 - 880 = 81 cm²

I hope my answer will help you

Answer 2

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▪Given that :-

• Length of the rectangle = 40 cm

•  Breadth of the rectangle = 22 cm

▪To Find :-

• Measure of Side.

• Shape encloses more area.

______________________________

Perimeter of rectangle = 2 (L + B)

Perimeter of square  = 4 × Side

Area of rectangle = Length × Breadth

Area of square = side × side

Let length of square is x

A.T.Q

Perimeter of rectangle = Perimeter of square

⇒ 2×(Length + Breadth) = 4 × x

⇒ 2 (40 + 22) = 4 × x

 ⇒ 2 × 62 = 4 × x

⇒  124 = 4 × x

 ⇒ x = 124/4

⇒ x = 31 cm

Area of rectangle =   40 × 22

Area of rectangle  = 880 cm²

Area of square = side × side

Area of square  = 31 × 31

Area of square   = 961 cm²

Hence, the measure of each side is 31 cm.

Hence, square shaped wire encloses more area.

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