find the nature size and position of image formed when an object of size 1 cm is placed at a distance of 72 cm from a convex mirror of focal length 36 cm
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HEY MATE, HERE IS UR ANSWER:-
Given:-
Object distance (u) = -72cm
Height of the object (h) = 1cm
Focal length of the mirror (f) = -36cm
By using mirror Formula,
1/v+1/u=1/f
1/v=1/f-1/u
1/v=1/(-36)-1/(-72)
1/v=1/(-36)+1/72
=-36+72/-72x72
1/v= 36/-2592
v=-2592/36= -72cm
Image distance= -72cm
Magnification (m)= h'/h= -v/u
= h'/1= -(-72)/-72
=h'/1= 72/-72
= 72= -72 h'
h'= -72/72
h'= -1cm
Height of the image is -1cm
Therefore the image formed is real, inverted and size of the image is equal to the object's size.
PLEASE MARK AS BRAINLIEST.
AND I HOPE THIS WILL HELP YOU.
Given:-
Object distance (u) = -72cm
Height of the object (h) = 1cm
Focal length of the mirror (f) = -36cm
By using mirror Formula,
1/v+1/u=1/f
1/v=1/f-1/u
1/v=1/(-36)-1/(-72)
1/v=1/(-36)+1/72
=-36+72/-72x72
1/v= 36/-2592
v=-2592/36= -72cm
Image distance= -72cm
Magnification (m)= h'/h= -v/u
= h'/1= -(-72)/-72
=h'/1= 72/-72
= 72= -72 h'
h'= -72/72
h'= -1cm
Height of the image is -1cm
Therefore the image formed is real, inverted and size of the image is equal to the object's size.
PLEASE MARK AS BRAINLIEST.
AND I HOPE THIS WILL HELP YOU.
soniyasonu162:
please mark as brainliest
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