.A wire is in the shape of square of side 24 cm. If the wire is bent into a
Rectangle of length 32 cm , find its breadth.
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perimeterofsquare4×sides=4×20=8
Perimeterofrectanglewireis80cm
2(x+b)=80
⇒24+b=40
(breadth)b=40−24=16cm
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Answer:
16cm
Step-by-step explanation:
length of wire = perimeter of square = 4×24cm = 96cm
perimeter of square = perimeter of rectangle = 2(l+b) = 2(32 +b)
=> 96 = 2×32 + 2b
=> 96 - 64 = 2b
=> 32/2= b= 16cm
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