Question

a wire is in the shape of the square of side 10 cm if the wire is rebent into the rectangle of 12 cm find its breadth which shape encloses more area and by how much

Answer 1

Perimeter of the square = 4× side
=> 4×10
= 40 cm
As the wire is bent into rectangle having length 12 cm
Since Perimeter of square = Perimeter of rectangle
40= 2(l+b)
20= 12+b
b= 8 cm
Area of square = 10²= 100 cm²
Area of rectangle= l×b= 12×8= 96cm²
Lost in area = 100-96= 4cm²

Answer 2

Answer:

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Step-by-step explanation:

Side of the square = 10 cm

Length of the wire = Perimeter of the square

= 4 x side

= 4 x 10cm

= 40 cm

Length of the rectangle, l = 12 cm. Let b be the breadth of the rectangle.

Perimeter of rectangle Length of wire = 40 cm

Perimeter of the rectangle = 2 (l + b)

40 = 2 (12 + b)

(OR) 40 / 2 = 12 + b

b = 20 - 12 = 8 cm

Therefore,The breadth of the rectangle is 8 cm.

Area of the square = (side)²

= 10 cm × 10 cm = 100cm²

Area of the rectangle = l × b

= 12cm × 8cm = 96cm²

So , the square encloses more area even though its perimeter is the same as that of the rectangle.