Question

. A wire is loaded by weight W, how elongation is affected if (a)load is doubled keeping other factors same (b)length is halved keeping other factors same?​

Answer 1

Answer:

In case (a), let Y be Young's modulus of the material of the 

wire. If a is its area of cross section, then we can write 

Y=l/LF/al/LF/a=alWl(∵F=W)

Increaseinlengthofwirel=aYWL

In case (b), we can treat either segment of length L/2

in Fig. 5] 7(b) as if one of its ends is fixed while the other end is

attached to the load W because the point M remains stationary, i.e.,

fixed all the time due to symmetrical load. Thus, when the wire is

passed over the pulley, let l be the increase in the length of each

segment. Since each segment is of length L/2, we have 

Y=al′W(L/2)

Increase in length of wire of one side of pulley 

l′=21aYWL=2l

Therefore, increase in length of both the segments of the wire

=l′+l′=l/2+l/2=l

So the increase in length remains the same.

Explanation:

Hope it helps

PLEASE MARK AS BRAINLIEST