Physics, asked by tushurajput31771, 8 months ago

a wire of 10ohm resistance was stretched to double its length.calculate the new resistance of the wire​

Answers

Answered by rudrakhushi62
1

Answer:

Half as thick doubles resistance, twice as long doubles that resistance. So multiply 10x2x2=40. The question should be a wire of resistance 10 ohm is stretched to double its length.

Explanation:

please mark brainlist answer

Answered by amulyamandokar
1

resistance = 10Ω

length = doubled

We know that resistance is directly proportional to the length of the conductor

therefore new resistance = double of original resistance

= (2*10)Ω

= 20Ω

Please mark my answer as the brainliest.

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