a wire of 3 ohm resistance and 10cm length is stretched to 30cm length.Assuming that it has a uniform cross section ,what will be it's new resistance. who so ever will answer I will be very thankful to that person.
Answers
Answered by
266
Original resistance = Ro = rho *l/A
The resistance of the conductor is directly proportional to its length and inversely proportional to its cross sectional area.
The wire is tripled of its previous length so the resistance will be 3l
and the new cross sectional area will be A/3
Rn = 3 * rho * l/ A/3
= 9R ( R = rho*l/A)
= 9*3 =27 Ohm
The resistance of the conductor is directly proportional to its length and inversely proportional to its cross sectional area.
The wire is tripled of its previous length so the resistance will be 3l
and the new cross sectional area will be A/3
Rn = 3 * rho * l/ A/3
= 9R ( R = rho*l/A)
= 9*3 =27 Ohm
Anonymous:
See, if you're not getting anything , feel free to ask !
can u tell it with formula roh length by area
can u tell how to mark it as brainiest
You need to answers for that !
yup
yippie
yup
yippie
yup
Answered by
82
The resistance of the conductor is directly proportional to its length and inversely proportional to its cross sectional area.
The wire is tripled of its previous length so the resistance will be 3l
and the new cross sectional area will be A/3
Rn = 3 * rho * l/ A/3
= 9R ( R = rho*l/A)
= 9*3 =27 Ohm
Yours truly,
Abba Ha.
Similar questions