Question

A wire of a certain material is stretched slowly by ten percent. Its new resistance and specific resistance become respectively​

Answer 1

1.12 times , same

R = P1/A

Now , 1=1+1/10=111/10

So RV= p × (111/10)/10A/11 = P1/A × (11^2)/(10^2) = 1.21R

Now resistance becomes 1.21 times of initial and specific resistance is the intrinsic property so remains same .

Answer 2

Answer:

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