a wire of &
A flows through
diameter 20 mm. Calculate the cennent density.
A cunnent of 12x10-10
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Explanation:
The current I in the uniform wire of diameter d1 i.e.
radius r1 with mean electron drift velocity v1 is given by,
I=ne4π(r1)2v1
if the same current flows through the wire of diameter 2d1 i.e radius 2r1 with drift velocity v2 is given by
I=ne4π(2r1)2v2
Therefore we can write
I=ne4π(r1)2v1=ne4π(2r1)2v2
⇒v1=4v2
∴v2=4v1
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